Maximum Power Transfer Theorem Definition And its solution Formula's

Maximum Power Transfer Theorem Definition And its solution Formula's

Maximum power transfer theorem can be explained by using Thevenin’s equivalent circuit. 

So, the problem of this theorem is also solved by same steps as we done in “Thevenin’s Theorem and method of solving”.

Here,

V_th replaced by V_o.c.

R_th replaced by R_o.c. &

R_L is same at is.

In maximum power transfer theorem, we are doing this process for open circuit. i.e, from where load-resistance R_L is removed.

Now,

Maximum power delivered to the load is found from the given condition is,

R_L= R_o.c ,This condition of states that the power delivered or transferred to load resistance is maximum when load-resistance equals the Thevenin’s equivalent resistance i.e, R_o.c is known as the “Maximum power transfer theorem”.

Then,

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Ques.) Find-out the value of current in 4Ω resistance for the given network by using Norton’s Theorem?

Sol.) For finding value of current through 4Ω resistance, we follow same steps discussed in Previous Post.

For finding R_L: -

Here, R_L= 4Ω

For finding R_N: - For finding R_N, Just find-out equivalent b/w removed load-resistance. Like as:-

For finding I_N/I_S.C: -

 Short-circuited Pt. A and Pt.  B, we have

When we Short-circuited then all current diverted through Short-circuited path and parallel resistances will remove. Like this:-

 Applying kvl in loop 1^st:-

8-2I₁-2I₁-2I₁+2I₂ =0

-6I₁+2I₂ = -8 ··············· (1)

Applying kvl in loop 2^nd:-

-2I₂-2I₂-2I₂+2I₁ =0

2I₁-6I₂ = 0    ··············· (2)

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On solving, we get

I₁ = 1.5A & I₂ = 0.5A

Here, I₂= I_s.c/ I_N = 0.5A

Now, the Norton’s equivalent circuit is,