Tuesday, 4 October 2022

How To Solve Problem Based On Norton’s Theorem In Practical

How To Solve Problem Based On Norton’s Theorem In Practical

In This Below Topic, We Will Discuss About “How To Solve Problem Based On Norton’s Theorem In Practical”.

Below Is The Example Of A Circuit Which We Will Find Answer By Solving Through Norton’s Theorem Method.

Reading Of Norton’s Theorem In Practical

Let’s Start.

Aim:- We Have To Find The Current In 4Ω Resistance In The Below Network Circuit By Using Norton’s Theorem.

Solve Problem Based On Norton’s Theorem In Practical

Solution: - For Solving The Value Of Current Through 4Ω Resistance, We Will Follow The Same Step As Discussed In Our Previous Post.

(Click Here To Revise Your Practice)

FOR FINDING R_L: -

HERE, R_L= 4Ω

NEXT STEP TO FIND R_N: -

For Finding R_N, Just Find-out Equivalent B/w Removed Load-resistance.

As Below:-

NEXT STEP TO FIND I_N/I_S.C: -

Next Step Is To Short-circuited Pt. A And Pt. B

How To Solve Problem Based On Norton’s Theorem In Practical

Now Current In The Circuit Will Easily Pass Through The Short Circuited Path And Parallel Resistance Will Remove, As Shown Below:-

In Below We Have Two Loop Circuit For Which We Get Current Of Each By Using Kirchhoff’s Voltage Law(KVL).

APPLY KVL IN LOOP 1^ST:-

8-2I₁-2I₁-2I₁+2I₂ =0

-6I₁+2I₂ = -8 ··············· (1)

APPLY KVL IN LOOP 2^ND:-

-2I₂-2I₂-2I₂+2I₁ =0

2I₁-6I₂ = 0 ··············· (2)

RESULT ON SOLVING, WE GET

I₁ = 1.5A & I₂ = 0.5A

HERE, I₂= I_S.C/ I_N = 0.5A

RESULT ON SOLVING, WE GET

I₁ = 1.5A & I₂ = 0.5A

HERE, I₂= I_S.C/ I_N = 0.5A

FINALLY, THE NORTON’S EQUIVALENT CIRCUIT IS,

Note:

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Wheatstone Bridge Definition:-

This is the simplest bridge to measure resistance. Figure 14.22 shows the schematic of a Wheatstone bridge. The bridge has four resistive arms together with a source of emf and detector, usually a galvanometer or other sensitive current meter.

If the sensitivity of the galvanometer is not sufficient to indicate the balance position to the required degree of precision, then the measured value of R, can have some error.

Thevenin Equivalent Circuit of Wheatstone Bridge:-

To find whether or not the galvanometer has the required sensitivity to detect an unbalance condition, it is necessary to calculate the galvanometer current. The Thevenin equivalent circuit is determined by looking into the galvanometer terminals 'c' and 'd' no as shown in Fig. 14.23.