How To Solve Problem Based On Norton’s Theorem In Practical

How To Solve Problem Based On Norton’s Theorem In Practical

In This Below Topic, We Will Discuss About “How To Solve Problem Based On Norton’s Theorem In Practical”.

Below Is The Example Of A Circuit Which We Will Find Answer By Solving Through Norton’s Theorem Method.

Let’s Start.

Aim:- We Have To Find The Current In 4Ω  Resistance In The Below Network Circuit By Using Norton’s Theorem.

Solution: - For Solving The Value Of Current Through 4Ω  Resistance, We Will Follow The Same Step As Discussed In Our Previous Post.

(Click Here To Revise Your Practice)

FOR FINDING R_L: -

 HERE, R_L= 4Ω

NEXT STEP TO FIND R_N: - 

For Finding R_N, Just Find-out Equivalent B/w Removed Load-resistance. 

As Below:-

NEXT STEP TO FIND I_N/I_S.C: -

Next Step Is To Short-circuited Pt. A And Pt.  B

Now Current In The Circuit Will Easily Pass Through The Short Circuited Path And Parallel Resistance Will Remove, As Shown Below:-

In Below We Have Two Loop Circuit For Which We Get Current Of Each By Using Kirchhoff’s Voltage Law(KVL).

APPLY KVL IN LOOP 1^ST:-

 8-2I₁-2I₁-2I₁+2I₂ =0

 -6I₁+2I₂ = -8 ··············· (1)

 

APPLY KVL IN LOOP 2^ND:-

 -2I₂-2I₂-2I₂+2I₁ =0

 2I₁-6I₂ = 0    ··············· (2)

RESULT ON SOLVING, WE GET

 I₁ = 1.5A & I₂ = 0.5A

 

HERE, I₂= I_S.C/ I_N = 0.5A

RESULT ON SOLVING, WE GET

 I₁ = 1.5A & I₂ = 0.5A

 HERE, I₂= I_S.C/ I_N = 0.5A

FINALLY, THE NORTON’S EQUIVALENT CIRCUIT IS,

Note: 

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