Solved problem based on Norton’s Theorem

Solved problem based on Norton’s Theorem

Ques.) Find-out the value of current in 4Ω resistance for the given network by using Norton’s Theorem?

Sol.) For finding value of current through 4Ω resistance, we follow same steps discussed in Previous Post.

For finding R_L: -

Here, R_L= 4Ω

For finding R_N: - For finding R_N, Just find-out equivalent b/w removed load-resistance. Like as:-

For finding I_N/I_S.C: -

 Short-circuited Pt. A and Pt.  B, we have

When we Short-circuited then all current diverted through Short-circuited path and parallel resistances will remove. Like this:-

 Applying kvl in loop 1^st:-

8-2I₁-2I₁-2I₁+2I₂ =0

-6I₁+2I₂ = -8 ··············· (1)

Applying kvl in loop 2^nd:-

-2I₂-2I₂-2I₂+2I₁ =0

2I₁-6I₂ = 0    ··············· (2)

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On solving, we get

I₁ = 1.5A & I₂ = 0.5A

Here, I₂= I_s.c/ I_N = 0.5A

Now, the Norton’s equivalent circuit is,